Print sum for each consequent 5 even numbers starting from 1. The loop will continue up to the 100.

Example of Output:

Sum: 30 [2,4,6,8,10 are the first 5 even number]

Sum: 90

etc.

Example of Output:

Sum: 30 [2,4,6,8,10 are the first 5 even number]

Sum: 90

etc.

I need help, Please help me, sir?

ReplyDelete/* Sum of each consequent 5 even number */

ReplyDelete/* Author name:Md-Naimul Hasan shohan */

#include

using namespace std;

void consequent()

{

cout<<"The first 5 even number are:"<<endl;

int count=0,sum=0;

for(int i=1;i<=100;i++)

{

if(i%2==0)

{

cout<<i<<"\t";

sum+=i;

count++;

if(count==5)

{

break;

}

}

}

cout<<endl;

cout<<"The sum of first 5 even number is:"<<sum;

}

int main()

{

consequent();

return 0;

}

/* Shahenur islam, ID: 201630405

ReplyDelete#include

using namespace std;

int main()

{

int i,j,count=1,b=0;

cout<<"First Ten Prime Numbers Are\n"<<"2";

for(i=3;i>0;++i)

{

for(j=2;j<=i/2;++j)

{

if(i%j==0){

b=1;

break;

}

}

if(b==0)

{

cout<<"\n"<<i;

count++;

}

b=0;

if(count==10)

break;

}

return 0;

}