Arithmetic Program


Write a program to print all numbers between 1 and 100 which are divisible by 9

7 comments:

  1. #include
    main()
    {
    int a,x=9;
    division(a,x);
    }

    int division(int m,int n)
    {
    printf("These numbers are divisable by 9 :\n");
    for (m=1;m<=100;m++)
    {
    if(m%n==0)
    {
    printf("\n%d\n",m);
    }
    }
    }

    ReplyDelete
  2. #include
    int divis(int i,int j);
    main()
    {
    int i=1,j=9;
    divis(i,j);
    }
    int divis(int a,int x)
    {
    while(a<=100)
    {
    if(a%x==0)
    {
    printf("%d\n",a);
    }
    a++;
    }
    }

    ReplyDelete
  3. #include
    #include
    int *funcx(void);
    int main()
    {
    int ptr;
    int (*pFn)(void);
    pFn=funcx;
    ptr=(*pFn)();
    getch();
    return 0;


    }

    int *funcx(void)
    {
    int n,i=9;
    printf("\n The divisable value are:");
    for(n=1;n<=100;n++)
    {
    if(n%i==0)
    printf("\n %d",n);

    }

    return n;
    }

    ReplyDelete
  4. #include
    main()
    {
    int a,x=9;
    division(a,x);
    }

    int division(int m,int n)
    {
    printf("These numbers are divisable by 9 :\n");
    for (m=1;m<=100;m++)
    {
    if(m%n==0)
    {
    printf("\n%d\n",m);
    }
    }
    }

    ReplyDelete
  5. #include
    #include
    int funcx(void);
    int main()
    {
    int ptr;
    ptr=funcx();
    printf("\n%d",ptr);
    getch();
    return 0;
    }
    int funcx(void)
    {
    int n,i=9;
    printf(" The divisable value are:");
    for(n=1;n<=100;n++)
    {
    if(n%i==0)
    printf("\n %d",n);
    }
    return n;
    }

    ReplyDelete
  6. #include
    main()
    {
    int i ;
    for(i=9;i<100;i++)
    {
    if(i%9==0)
    printf("%d\n",i);

    }
    }

    ReplyDelete
    Replies
    1. #include
      main()
      {
      int a;
      for(a=9;a<=100;a++)
      {
      if(a%9==0)
      printf("Arithmetic Program is %d\n",a);
      }
      }

      Delete